x^2+9x+6x+18=60

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Solution for x^2+9x+6x+18=60 equation:



x^2+9x+6x+18=60
We move all terms to the left:
x^2+9x+6x+18-(60)=0
We add all the numbers together, and all the variables
x^2+15x-42=0
a = 1; b = 15; c = -42;
Δ = b2-4ac
Δ = 152-4·1·(-42)
Δ = 393
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{393}}{2*1}=\frac{-15-\sqrt{393}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{393}}{2*1}=\frac{-15+\sqrt{393}}{2} $

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